3b^2-17b+20=-4

Solution for 3b^2-17b+20=-4 equation:

3b^2-17b+20=-4

We move all terms to the left:

3b^2-17b+20-(-4)=0

We add all the numbers together, and all the variables

3b^2-17b+24=0

a = 3; b = -17; c = +24;
Δ = b2-4ac
Δ = -172-4·3·24
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-1}{2*3}=\frac{16}{6}
=2+2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+1}{2*3}=\frac{18}{6}
=3
$